Аналіз I, Глава 4.3
I have attempted to make the translation as faithful a paraphrasing as possible of the original text. When there is a choice between a more idiomatic Lean solution and a more faithful translation, I have generally chosen the latter. In particular, there will be places where the Lean code could be "golfed" to be more elegant and idiomatic, but I have consciously avoided doing so.
Main constructions and results of this section:
-
Basic properties of absolute value and exponentiation on the rational numbers (here we use the Mathlib rational numbers
ℚ
rather than the Section 4.2 rational numbers).
Note: to avoid notational conflict, we are using the standard Mathlib definitions of absolute value and exponentiation. As such, it is possible to solve several of the exercises here rather easily using the Mathlib API for these operations. However, the spirit of the exercises is to solve these instead using the API provided in this section, as well as more basic Mathlib API for the rational numbers that does not reference either absolute value or exponentiation.
This definition needs to be made outside of the Section 4.3 namespace for technical reasons.
def Rat.close (ε : ℚ) (x y:ℚ) := |x-y| ≤ ε
namespace Section_4_3
Визначення 4.3.1 (Absolute value)
abbrev abs (x:ℚ) : ℚ := if x > 0 then x else (if x < 0 then -x else 0)
theorem abs_of_pos {x: ℚ} (hx: x > 0) : abs x = x := x:ℚhx:x > 0⊢ abs x = x All goals completed! 🐙
Визначення 4.3.1 (Absolute value)
theorem abs_of_neg {x: ℚ} (hx: x < 0) : abs x = -x := x:ℚhx:x < 0⊢ abs x = -x
x:ℚhx:x < 0⊢ 0 < x → x = -x
x:ℚhx:x < 0hx':0 < x⊢ x = -x
All goals completed! 🐙
Визначення 4.3.1 (Absolute value)
theorem abs_of_zero : abs 0 = 0 := ⊢ abs 0 = 0 All goals completed! 🐙
(Не із книги) This definition of absolute value agrees with the Mathlib one. Henceforth we use the Mathlib absolute value.
theorem abs_eq_abs (x: ℚ) : abs x = |x| := x:ℚ⊢ abs x = |x|
All goals completed! 🐙
abbrev dist (x y : ℚ) := |x - y|
Визначення 4.2 (Distance). We avoid the Mathlib notion of distance here because it is real-valued.
theorem dist_eq (x y: ℚ) : dist x y = |x-y| := rfl
Твердження 4.3.3(a) / Вправа 4.3.1
theorem abs_nonneg (x: ℚ) : |x| ≥ 0 := x:ℚ⊢ |x| ≥ 0 All goals completed! 🐙
Твердження 4.3.3(a) / Вправа 4.3.1
theorem abs_eq_zero_iff (x: ℚ) : |x| = 0 ↔ x = 0 := x:ℚ⊢ |x| = 0 ↔ x = 0 All goals completed! 🐙
Твердження 4.3.3(b) / Вправа 4.3.1
theorem abs_add (x y:ℚ) : |x + y| ≤ |x| + |y| := x:ℚy:ℚ⊢ |x + y| ≤ |x| + |y| All goals completed! 🐙
Твердження 4.3.3(c) / Вправа 4.3.1
theorem abs_le_iff (x y:ℚ) : -y ≤ x ∧ x ≤ y ↔ |x| ≤ y := x:ℚy:ℚ⊢ -y ≤ x ∧ x ≤ y ↔ |x| ≤ y All goals completed! 🐙
Твердження 4.3.3(c) / Вправа 4.3.1
theorem le_abs (x:ℚ) : -|x| ≤ x ∧ x ≤ |x| := x:ℚ⊢ -|x| ≤ x ∧ x ≤ |x| All goals completed! 🐙
Твердження 4.3.3(d) / Вправа 4.3.1
theorem abs_mul (x y:ℚ) : |x * y| = |x| * |y| := x:ℚy:ℚ⊢ |x * y| = |x| * |y| All goals completed! 🐙
Твердження 4.3.3(d) / Вправа 4.3.1
theorem abs_neg (x:ℚ) : |-x| = |x| := x:ℚ⊢ |(-x)| = |x| All goals completed! 🐙
Твердження 4.3.3(e) / Вправа 4.3.1
theorem dist_nonneg (x y:ℚ) : dist x y ≥ 0 := x:ℚy:ℚ⊢ dist x y ≥ 0 All goals completed! 🐙
Твердження 4.3.3(e) / Вправа 4.3.1
theorem dist_eq_zero_iff (x y:ℚ) : dist x y = 0 ↔ x = y := x:ℚy:ℚ⊢ dist x y = 0 ↔ x = y
All goals completed! 🐙
Твердження 4.3.3(f) / Вправа 4.3.1
theorem dist_symm (x y:ℚ) : dist x y = dist y x := x:ℚy:ℚ⊢ dist x y = dist y x All goals completed! 🐙
Твердження 4.3.3(f) / Вправа 4.3.1
theorem dist_le (x y z:ℚ) : dist x z ≤ dist x y + dist y z := x:ℚy:ℚz:ℚ⊢ dist x z ≤ dist x y + dist y z All goals completed! 🐙
Визначення 4.3.4 (eps-closeness). In the text the notion is undefined for ε zero or negative, but it is more convenient in Lean to assign a "junk" definition in this case. But this also allows some relaxations of hypotheses in the lemmas that follow.
theorem close_iff (ε x y:ℚ): ε.close x y ↔ |x - y| ≤ ε := ε:ℚx:ℚy:ℚ⊢ ε.close x y ↔ |x - y| ≤ ε All goals completed! 🐙
Приклади 4.3.6
example : (0.1:ℚ).close (0.99:ℚ) (1.01:ℚ) := ⊢ Rat.close 0.1 0.99 1.01 All goals completed! 🐙
Приклади 4.3.6
example : ¬ (0.01:ℚ).close (0.99:ℚ) (1.01:ℚ) := ⊢ ¬Rat.close 1e-2 0.99 1.01 All goals completed! 🐙
Приклади 4.3.6
example (ε : ℚ) (hε : ε > 0) : ε.close 2 2 := ε:ℚhε:ε > 0⊢ ε.close 2 2 All goals completed! 🐙
theorem close_refl (x:ℚ) : (0:ℚ).close x x := x:ℚ⊢ Rat.close 0 x x All goals completed! 🐙
Твердження 4.3.7(a) / Вправа 4.3.2
theorem eq_if_close (x y:ℚ) : x = y ↔ ∀ ε:ℚ, ε > 0 → ε.close x y := x:ℚy:ℚ⊢ x = y ↔ ∀ ε > 0, ε.close x y All goals completed! 🐙
Твердження 4.3.7(b) / Вправа 4.3.2
theorem close_symm (ε x y:ℚ) : ε.close x y ↔ ε.close y x := ε:ℚx:ℚy:ℚ⊢ ε.close x y ↔ ε.close y x All goals completed! 🐙
Твердження 4.3.7(c) / Вправа 4.3.2
theorem close_trans {ε δ x y:ℚ} (hxy: ε.close x y) (hyz: δ.close y z) :
(ε + δ).close x z := z:ℚε:ℚδ:ℚx:ℚy:ℚhxy:ε.close x yhyz:δ.close y z⊢ (ε + δ).close x z All goals completed! 🐙
Твердження 4.3.7(d) / Вправа 4.3.2
theorem add_close {ε δ x y z w:ℚ} (hxy: ε.close x y) (hzw: δ.close z w) :
(ε + δ).close (x+z) (y+w) := ε:ℚδ:ℚx:ℚy:ℚz:ℚw:ℚhxy:ε.close x yhzw:δ.close z w⊢ (ε + δ).close (x + z) (y + w) All goals completed! 🐙
Твердження 4.3.7(d) / Вправа 4.3.2
theorem sub_close {ε δ x y z w:ℚ} (hxy: ε.close x y) (hzw: δ.close z w) :
(ε + δ).close (x-z) (y-w) := ε:ℚδ:ℚx:ℚy:ℚz:ℚw:ℚhxy:ε.close x yhzw:δ.close z w⊢ (ε + δ).close (x - z) (y - w) All goals completed! 🐙
Твердження 4.3.7(e) / Вправа 4.3.2, slightly strengthened
theorem close_mono {ε ε' x y:ℚ} (hxy: ε.close x y) (hε: ε' ≥ ε) :
ε'.close x y := ε:ℚε':ℚx:ℚy:ℚhxy:ε.close x yhε:ε' ≥ ε⊢ ε'.close x y All goals completed! 🐙
Твердження 4.3.7(f) / Вправа 4.3.2
theorem close_between {ε x y z w:ℚ} (hxy: ε.close x y) (hyz: ε.close x z)
(hbetween: (y ≤ w ∧ w ≤ z) ∨ (z ≤ w ∧ w ≤ y)) : ε.close x w := ε:ℚx:ℚy:ℚz:ℚw:ℚhxy:ε.close x yhyz:ε.close x zhbetween:y ≤ w ∧ w ≤ z ∨ z ≤ w ∧ w ≤ y⊢ ε.close x w All goals completed! 🐙
Твердження 4.3.7(g) / Вправа 4.3.2
theorem close_mul_right {ε x y z:ℚ} (hε: ε ≥ 0) (hxy: ε.close x y) :
(ε*|z|).close (x * z) (y * z) := ε:ℚx:ℚy:ℚz:ℚhε:ε ≥ 0hxy:ε.close x y⊢ (ε * |z|).close (x * z) (y * z) All goals completed! 🐙
Твердження 4.3.7(h) / Вправа 4.3.2
theorem close_mul_mul {ε δ x y z w:ℚ} (hε: ε ≥ 0) (hxy: ε.close x y) (hzw: δ.close z w) :
(ε*|z|+δ*|x|+ε*δ).close (x * z) (y * w) := ε:ℚδ:ℚx:ℚy:ℚz:ℚw:ℚhε:ε ≥ 0hxy:ε.close x yhzw:δ.close z w⊢ (ε * |z| + δ * |x| + ε * δ).close (x * z) (y * w)
-- The proof is written to follow the structure of the original text, though on formalization it was revealed that the hypothesis δ ≥ 0 was unnecessary.
ε:ℚδ:ℚx:ℚy:ℚz:ℚw:ℚhε:ε ≥ 0hxy:ε.close x yhzw:δ.close z wa:ℚ := y - x⊢ (ε * |z| + δ * |x| + ε * δ).close (x * z) (y * w)
have ha : y = x + a := ε:ℚδ:ℚx:ℚy:ℚz:ℚw:ℚhε:ε ≥ 0hxy:ε.close x yhzw:δ.close z w⊢ (ε * |z| + δ * |x| + ε * δ).close (x * z) (y * w) All goals completed! 🐙
have haε: |a| ≤ ε := ε:ℚδ:ℚx:ℚy:ℚz:ℚw:ℚhε:ε ≥ 0hxy:ε.close x yhzw:δ.close z w⊢ (ε * |z| + δ * |x| + ε * δ).close (x * z) (y * w) rwa [close_symm, close_iffε:ℚδ:ℚx:ℚy:ℚz:ℚw:ℚhε:ε ≥ 0hxy:|y - x| ≤ εhzw:δ.close z wa:ℚ := y - xha:y = x + a⊢ |a| ≤ ε at hxy
ε:ℚδ:ℚx:ℚy:ℚz:ℚw:ℚhε:ε ≥ 0hxy:ε.close x yhzw:δ.close z wa:ℚ := y - xha:y = x + ahaε:|a| ≤ εb:ℚ := w - z⊢ (ε * |z| + δ * |x| + ε * δ).close (x * z) (y * w)
have hb : w = z + b := ε:ℚδ:ℚx:ℚy:ℚz:ℚw:ℚhε:ε ≥ 0hxy:ε.close x yhzw:δ.close z w⊢ (ε * |z| + δ * |x| + ε * δ).close (x * z) (y * w) All goals completed! 🐙
have hbδ: |b| ≤ δ := ε:ℚδ:ℚx:ℚy:ℚz:ℚw:ℚhε:ε ≥ 0hxy:ε.close x yhzw:δ.close z w⊢ (ε * |z| + δ * |x| + ε * δ).close (x * z) (y * w) rwa [close_symm, close_iffε:ℚδ:ℚx:ℚy:ℚz:ℚw:ℚhε:ε ≥ 0hxy:ε.close x yhzw:|w - z| ≤ δa:ℚ := y - xha:y = x + ahaε:|a| ≤ εb:ℚ := w - zhb:w = z + b⊢ |b| ≤ δ at hzw
have : y*w = x * z + a * z + x * b + a * b := ε:ℚδ:ℚx:ℚy:ℚz:ℚw:ℚhε:ε ≥ 0hxy:ε.close x yhzw:δ.close z w⊢ (ε * |z| + δ * |x| + ε * δ).close (x * z) (y * w) ε:ℚδ:ℚx:ℚy:ℚz:ℚw:ℚhε:ε ≥ 0hxy:ε.close x yhzw:δ.close z wa:ℚ := y - xha:y = x + ahaε:|a| ≤ εb:ℚ := w - zhb:w = z + bhbδ:|b| ≤ δ⊢ (x + a) * (z + b) = x * z + a * z + x * b + a * b; All goals completed! 🐙
ε:ℚδ:ℚx:ℚy:ℚz:ℚw:ℚhε:ε ≥ 0hxy:ε.close x yhzw:δ.close z wa:ℚ := y - xha:y = x + ahaε:|a| ≤ εb:ℚ := w - zhb:w = z + bhbδ:|b| ≤ δthis:y * w = x * z + a * z + x * b + a * b⊢ |y * w - x * z| ≤ ε * |z| + δ * |x| + ε * δ
calc
_ = |a * z + b * x + a * b| := ε:ℚδ:ℚx:ℚy:ℚz:ℚw:ℚhε:ε ≥ 0hxy:ε.close x yhzw:δ.close z wa:ℚ := y - xha:y = x + ahaε:|a| ≤ εb:ℚ := w - zhb:w = z + bhbδ:|b| ≤ δthis:y * w = x * z + a * z + x * b + a * b⊢ |y * w - x * z| = |a * z + b * x + a * b| ε:ℚδ:ℚx:ℚy:ℚz:ℚw:ℚhε:ε ≥ 0hxy:ε.close x yhzw:δ.close z wa:ℚ := y - xha:y = x + ahaε:|a| ≤ εb:ℚ := w - zhb:w = z + bhbδ:|b| ≤ δthis:y * w = x * z + a * z + x * b + a * b⊢ |x * z + a * z + x * b + a * b - x * z| = |a * z + b * x + a * b|; ε:ℚδ:ℚx:ℚy:ℚz:ℚw:ℚhε:ε ≥ 0hxy:ε.close x yhzw:δ.close z wa:ℚ := y - xha:y = x + ahaε:|a| ≤ εb:ℚ := w - zhb:w = z + bhbδ:|b| ≤ δthis:y * w = x * z + a * z + x * b + a * b⊢ x * z + a * z + x * b + a * b - x * z = a * z + b * x + a * b; All goals completed! 🐙
_ ≤ |a * z + b * x| + |a * b| := abs_add _ _
_ ≤ |a * z| + |b * x| + |a * b| := ε:ℚδ:ℚx:ℚy:ℚz:ℚw:ℚhε:ε ≥ 0hxy:ε.close x yhzw:δ.close z wa:ℚ := y - xha:y = x + ahaε:|a| ≤ εb:ℚ := w - zhb:w = z + bhbδ:|b| ≤ δthis:y * w = x * z + a * z + x * b + a * b⊢ |a * z + b * x| + |a * b| ≤ |a * z| + |b * x| + |a * b|
ε:ℚδ:ℚx:ℚy:ℚz:ℚw:ℚhε:ε ≥ 0hxy:ε.close x yhzw:δ.close z wa:ℚ := y - xha:y = x + ahaε:|a| ≤ εb:ℚ := w - zhb:w = z + bhbδ:|b| ≤ δthis:y * w = x * z + a * z + x * b + a * b⊢ |a * z + b * x| ≤ |a * z| + |b * x|; All goals completed! 🐙
_ = |a| * |z| + |b| * |x| + |a| * |b| := ε:ℚδ:ℚx:ℚy:ℚz:ℚw:ℚhε:ε ≥ 0hxy:ε.close x yhzw:δ.close z wa:ℚ := y - xha:y = x + ahaε:|a| ≤ εb:ℚ := w - zhb:w = z + bhbδ:|b| ≤ δthis:y * w = x * z + a * z + x * b + a * b⊢ |a * z| + |b * x| + |a * b| = |a| * |z| + |b| * |x| + |a| * |b|
All goals completed! 🐙
_ ≤ _ := ε:ℚδ:ℚx:ℚy:ℚz:ℚw:ℚhε:ε ≥ 0hxy:ε.close x yhzw:δ.close z wa:ℚ := y - xha:y = x + ahaε:|a| ≤ εb:ℚ := w - zhb:w = z + bhbδ:|b| ≤ δthis:y * w = x * z + a * z + x * b + a * b⊢ |a| * |z| + |b| * |x| + |a| * |b| ≤ ε * |z| + δ * |x| + ε * δ
All goals completed! 🐙
Визначення 4.3.9 (exponentiation). Here we use the Mathlib definition.
lemma pow_zero (x:ℚ) : x^0 = 1 := rfl
example : (0:ℚ)^0 = 1 := pow_zero 0
Визначення 4.3.9 (exponentiation). Here we use the Mathlib definition.
lemma pow_succ (x:ℚ) (n:ℕ) : x^(n+1) = x^n * x := _root_.pow_succ x n
Твердження 4.3.10 (Properties of exponentiation, I) / Вправа 4.3.3
theorem pow_add (x:ℚ) (m n:ℕ) : x^n * x^m = x^(n+m) := x:ℚm:ℕn:ℕ⊢ x ^ n * x ^ m = x ^ (n + m) All goals completed! 🐙
Твердження 4.3.10(a) (Properties of exponentiation, I) / Вправа 4.3.3
theorem pow_mul (x:ℚ) (m n:ℕ) : (x^n)^m = x^(n*m) := x:ℚm:ℕn:ℕ⊢ (x ^ n) ^ m = x ^ (n * m) All goals completed! 🐙
Твердження 4.3.10(a) (Properties of exponentiation, I) / Вправа 4.3.3
theorem mul_pow (x y:ℚ) (n:ℕ) : (x*y)^n = x^n * y^n := x:ℚy:ℚn:ℕ⊢ (x * y) ^ n = x ^ n * y ^ n All goals completed! 🐙
Твердження 4.3.10(b) (Properties of exponentiation, I) / Вправа 4.3.3
theorem pow_eq_zero (x:ℚ) (n:ℕ) : x^n = 0 ↔ x = 0 := x:ℚn:ℕ⊢ x ^ n = 0 ↔ x = 0 All goals completed! 🐙
Твердження 4.3.10(c) (Properties of exponentiation, I) / Вправа 4.3.3
theorem pow_nonneg {x:ℚ} (n:ℕ) (hx: x ≥ 0) : x^n ≥ 0 := x:ℚn:ℕhx:x ≥ 0⊢ x ^ n ≥ 0 All goals completed! 🐙
Твердження 4.3.10(c) (Properties of exponentiation, I) / Вправа 4.3.3
theorem pow_pos {x:ℚ} (n:ℕ) (hx: x > 0) : x^n > 0 := x:ℚn:ℕhx:x > 0⊢ x ^ n > 0 All goals completed! 🐙
Твердження 4.3.10(c) (Properties of exponentiation, I) / Вправа 4.3.3
theorem pow_ge_pow (x y:ℚ) (n:ℕ) (hxy: x ≥ y) (hy: y ≥ 0) : x^n ≥ y^n := x:ℚy:ℚn:ℕhxy:x ≥ yhy:y ≥ 0⊢ x ^ n ≥ y ^ n All goals completed! 🐙
Твердження 4.3.10(c) (Properties of exponentiation, I) / Вправа 4.3.3
theorem pow_gt_pow (x y:ℚ) (n:ℕ) (hxy: x > y) (hy: y ≥ 0) (hn: n > 0) : x^n > y^n := x:ℚy:ℚn:ℕhxy:x > yhy:y ≥ 0hn:n > 0⊢ x ^ n > y ^ n All goals completed! 🐙
Твердження 4.3.10(d) (Properties of exponentiation, I) / Вправа 4.3.3
theorem pow_abs (x:ℚ) (n:ℕ) : |x|^n = |x^n| := x:ℚn:ℕ⊢ |x| ^ n = |x ^ n| All goals completed! 🐙
Визначення 4.3.11 (Exponentiation to a negative number). Here we use the Mathlib notion of integer exponentiation
theorem zpow_neg (x:ℚ) (n:ℕ) : x^(-(n:ℤ)) = 1/(x^n) := x:ℚn:ℕ⊢ x ^ (-↑n) = 1 / x ^ n
All goals completed! 🐙
example (x:ℚ): x^(-3:ℤ) = 1/(x^3) := zpow_neg x 3
example (x:ℚ): x^(-3:ℤ) = 1/(x*x*x) := x:ℚ⊢ x ^ (-3) = 1 / (x * x * x)
x:ℚ⊢ x * x * x = x ^ 3; All goals completed! 🐙
theorem pow_eq_zpow (x:ℚ) (n:ℕ): x^(n:ℤ) = x^n := zpow_natCast x n
Твердження 4.3.12(a) (Properties of exponentiation, II) / Вправа 4.3.4
theorem zpow_add (x:ℚ) (n m:ℤ) : x^n * x^m = x^(n+m) := x:ℚn:ℤm:ℤ⊢ x ^ n * x ^ m = x ^ (n + m) All goals completed! 🐙
Твердження 4.3.12(a) (Properties of exponentiation, II) / Вправа 4.3.4
theorem zpow_mul (x:ℚ) (n m:ℤ) : (x^n)^m = x^(n*m) := x:ℚn:ℤm:ℤ⊢ (x ^ n) ^ m = x ^ (n * m) All goals completed! 🐙
Твердження 4.3.12(a) (Properties of exponentiation, II) / Вправа 4.3.4
theorem mul_zpow (x y:ℚ) (n:ℤ) : (x*y)^n = x^n * y^n := x:ℚy:ℚn:ℤ⊢ (x * y) ^ n = x ^ n * y ^ n All goals completed! 🐙
Твердження 4.3.12(b) (Properties of exponentiation, II) / Вправа 4.3.4
theorem zpow_pos {x:ℚ} (n:ℤ) (hx: x > 0) : x^n > 0 := x:ℚn:ℤhx:x > 0⊢ x ^ n > 0 All goals completed! 🐙
Твердження 4.3.12(b) (Properties of exponentiation, II) / Вправа 4.3.4
theorem zpow_ge_zpow {x y:ℚ} {n:ℤ} (hxy: x ≥ y) (hy: y > 0) (hn: n > 0): x^n ≥ y^n := x:ℚy:ℚn:ℤhxy:x ≥ yhy:y > 0hn:n > 0⊢ x ^ n ≥ y ^ n All goals completed! 🐙
theorem zpow_ge_zpow_ofneg {x y:ℚ} {n:ℤ} (hxy: x ≥ y) (hy: y > 0) (hn: n < 0) : x^n ≤ y^n := x:ℚy:ℚn:ℤhxy:x ≥ yhy:y > 0hn:n < 0⊢ x ^ n ≤ y ^ n
All goals completed! 🐙
Твердження 4.3.12(c) (Properties of exponentiation, II) / Вправа 4.3.4
theorem zpow_inj {x y:ℚ} {n:ℤ} (hx: x > 0) (hy : y > 0) (hn: n ≠ 0) (hxy: x^n = y^n) : x = y := x:ℚy:ℚn:ℤhx:x > 0hy:y > 0hn:n ≠ 0hxy:x ^ n = y ^ n⊢ x = y
All goals completed! 🐙
Твердження 4.3.12(d) (Properties of exponentiation, II) / Вправа 4.3.4
theorem zpow_abs (x:ℚ) (n:ℤ) (hx: x ≠ 0) : |x|^n = |x^n| := x:ℚn:ℤhx:x ≠ 0⊢ |x| ^ n = |x ^ n| All goals completed! 🐙